林苡嫻程式設計HTML.CSS.JavaScript.Java

w3schools截圖 w3schools程式碼 #林苡嫻 集合{},清單[],元組(),字典{key:value} s = {"台積電", "鴻海", "聯發科", "中華電", "台塑化"} t = ("台積電", "鴻海", "聯發科", "中華電", "台塑化") list = ["台積電", "鴻海", "聯發科"] d = {2330:"台積電", 2317:"鴻海", 2454:"聯發科"} print("s型態" + str(type(s))) print("t型態" + str(type(t))) print("d型態" + str(type(d))) print("t型態" + str(type(list))) #字串與字串+ i = 0 for a in t: i = i + 1 print("台灣市場價格第" + str(i) + "大公司是") print(" " + a) print("聯發科的位置" + str(t.index("聯發科"))) '''python大區塊的註解，前後用三個引號 str 轉成字串 int 轉成數字 ''' w3schools元組tuples的方法 Python has two built-in methods that you can use on tuples. Method Description count() Returns the number of times a specified value occurs in a tuple index() Searches the tuple for a...

w3schools截圖 w3schools程式碼 #林苡嫻 字典 keys:value市場價值最大的公司 a = { 2330: "台積電", 2317: "鴻海", 2454: "聯發科", 2412: "中華電", 6505:"台塑化",2308: "台達電"} print(a) print("迴圈列出字典的所有值") for t in a: print(a[t]) b = a.copy() #字典不能直接assign print(b) a.update({2881:"富邦金控"})#台灣第七大 a.update({2303:"聯電"}) #台灣大八大 for t in a: print(a[t]) a.setdefault(1303,"南亞") a.setdefault(2882,"國泰金") i = 0 for t in a: #python迴圈不使用{...}縮排整齊整齊 i = i + 1 print("台灣第" + str(i) + a[t]) w3schools字典方法列表   Method Description clear() Removes all the elements from the dictionary copy() Returns a copy of the dictionary fromkeys() Returns a dictionary with the specified keys and value get() Returns the value of the specified key items() Returns a list containing a tuple for each key value pair keys() Returns a list containing the dictionary's keys pop() Removes the element with the specified key ...

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#林苡嫻2023.03.06 b = "劉德華大烏龜" #python字串單或雙引號都可 # 0 1 2 3 4 5 6 # -6-5-4-3-2-1 print("字串長度:"+str(len(b))) #相同字串型態才能串接 print("反過來:"+b[::-1]) print(b[:3]) #b字串的0,1,2 print(b[-4:-1]) print(b[-8:-4]) x = '火鍋' y = 9999 myorder = "我希望 {2} 陪我去吃 {0} 他付錢 {1}." print(myorder.format(x, y, b)) # format的參數 0, 1, 2